Rationalise the denominator of √6by√3-√2
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Answered by
3
Answer:
Hey
here's your answer !!
√6 / ( √3-√2 )
= √6 ( √3 + √2 ) / ( √3-√2 )( √3 + √2 )
= ( √6 * √3 ) + ( √6 * √2 ) / ( √3 )² - ( √2 )²
= √18 + √12 / ( 3 -2 )
= 3√2 +2√3 ( ANSWER )
hope it helps !!
Answered by
8
Step-by-step explanation:
hey mate upar neeche route 3+ route 2 se multiply kar do .......
neeche a square -b square ka formula ban jayega upar multiply kar dena ho jayega....❤
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