Math, asked by lokesh7993, 11 months ago

Rationalise the denominator of √6by√3-√2

Answers

Answered by ramankumar13452005
3

Answer:

Hey

here's your answer !!

√6 / ( √3-√2 )

= √6 ( √3 + √2 ) / ( √3-√2 )( √3 + √2 )

= ( √6 * √3 ) + ( √6 * √2 ) / ( √3 )² - ( √2 )²

= √18 + √12 / ( 3 -2 )

= 3√2 +2√3 ( ANSWER )

hope it helps !!

Answered by aksingh57
8

Step-by-step explanation:

hey mate upar neeche route 3+ route 2 se multiply kar do .......

neeche a square -b square ka formula ban jayega upar multiply kar dena ho jayega....❤

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