Question

Rationalise the denominator of 7+√3
√7-√2
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Answer 1

Answer:

$\frac{7 + \sqrt{3} }{ \sqrt{7} - \sqrt{2} } \\ \\ = \frac{7 + \sqrt{3} }{ \sqrt{7} - \sqrt{2} } \times \frac{ \sqrt{7} + \sqrt{2} }{ \sqrt{7} + \sqrt{2} } \\ \\ = \frac{(7 + \sqrt{3})( \sqrt{7} + \sqrt{2} )}{ {( \sqrt{7}) }^{2} - {( \sqrt{2} )}^{2} } \\ \\ = \frac{7 \sqrt{7} + 7 \sqrt{2} + \sqrt{21} + \sqrt{6} }{7 - 2} \\ \\ = \frac{7 \sqrt{7} + 7 \sqrt{2} + \sqrt{21} + \sqrt{6} }{5}$

hope this much helps uh ❣️