Math, asked by tageankha25, 1 year ago

Rationalise the denominator of √7 / √5-√6

Answers

Answered by Shahoodalam
0

 \frac{ \sqrt{7} }{ \sqrt{5}  -  \sqrt{6} }  \\now \: we \: multiply \: by \: denomenator \: in \:  \\ both \: numerator \: and \: denomenator \\   \frac{ \sqrt{7} }{( \sqrt{5} - \sqrt{6}  )}  \times  \frac{ \sqrt{5 }  +  \sqrt{6} }{ \sqrt{5}  +  \sqrt{6} }  \\  \frac{ \sqrt{7 } \times ( \sqrt{5}   + \sqrt{6} )}{( \sqrt{5}  -  \sqrt{6} )( \sqrt{5} +  \sqrt{6} ) }  \\  \frac{ \sqrt{35} + \sqrt{42}  }{(5  - 6 )}  \\  \frac{ \sqrt{35}  + \sqrt{42} }{(-1)}  \:  \: answer \:

I hope that helps you..........

Answered by danishjibran
0

Answer:

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