Question

Rationalise the denominator of 8/square root 11 - square root 7

Answer 1

$= > \frac{8}{ \sqrt{11} - \sqrt{7} }$

$= > \frac{8}{ \sqrt{11} - \sqrt{7} } \times \frac{ \sqrt{11} + \sqrt{7} }{ \sqrt{11} + \sqrt{7} }$

$= > \frac{8( \sqrt{11} + \sqrt{7}) }{11 -7 }$

$= > \frac{8( \sqrt{11} + \sqrt{7}) }{4}$

$= > 2( \sqrt{11} + \sqrt{7} )$

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