Question

rationalise the denominator of :;​

Answer 1

√3+√2+1/√3square-√2+1square

√3+√2+1/3+3

√3+√2+1/6

Answer 2

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=> $\frac{1}{√3 ~ - ~√2 ~+~1}$

=> $\frac{1}{√3-√2+1}$ × $\frac{(√3-√2)-1}{(√3-√2)-1}$

=> $\frac{√3-√2-1}{ (√3-√2)²-(1)² }$

=> $\frac{√3-√2-1}{ (√3)² - 2√6+(√2)²-1 }$

=> $\frac{√3-√2-1}{(3-2√6+2-1)}$

=> $\frac{√3-√2-1}{(4-2√6)}$

=> $\frac{√3-√2-1}{2(2-√6)}$

=> $\frac{√3-√2-1}{2(2√6}$ × $\frac{2+√6}{2+√6}$

=> $\frac{2√3-2√2-2+√18-√12-√6}{2(2)²-(√6)²}$

=> $\frac{2√3-2√2-2+3√2-2√3-√6}{2(4-6)}$

=> $\frac{ √2~-~2~-~√6}{ 2(-2) }$

=> $\frac{ √2~-~2~-~√6}{ -4}$

==> $\frac{1}{4(2~+~√6~-~√6}$ ☑️

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