Question

Rationalise the denominator of each of the following
√5/2√3
​

Answer 1

Answer:

We rationalise the denominator of (32−552−3) by multiplying its rationalising factor (32+5) in the numerator and denominator as follows: 

           

32−552−3×32+532+5=(32−5)(32+5)(52−3)(32+5)=

(32)2−(5)252(32+5)−3(32+5)=(9×2)−5(5×32×2)+(52×5)−(33×2)−(3×5)

=18−5154+510−36−15=13(15×2)+510−36−15=1330+510−36−15    

  

Hence, 32−552−3=1330+510−36−15

Answer 2

Step-by-step explanation:

root 5/2root3= 2root 15/6