Question

Rationalise the denominator of each of the following (i-vii) :
(i) 3/√5 (ii)3/2√5 (iii)1/√12 (iv) √2/√5 (v) √3 + 1/√2 (vi) √2 + √5 / √3 (vii) 3√2/√5

Answer 1

(i) Given : 3/√5  

The Rationalising factor of the denominator is  √5.  

= (3 × √5) /(√5  ×√5)

= (3√5) /5  

 

(ii) 3/2√5  

The Rationalising factor of the denominator is  √5.  

=  (3 × √5) / (2√5 × √5))

=  (3√5) / (2 × 5)

=  (3√5) / 10  

 

(iii)1/√12  

The Rationalising factor of the denominator is  √12.  

= (1 × √12 )/(√12 × √12)

= √12/12

= √(4 × 3)/12

= 2√3/12

= √3/6

 

(iv) √2/√5  

The Rationalising factor of the denominator is  √5.  

= (√2 × √5)/(√5 × √5)

= √10/5

 

(v) √3 + 1/√2  

The Rationalising factor of the denominator is  √2.  

= (√3 + 1) × √2 /√2 × √2

= [√3 × √2 + √2)/2

= (√6 + √2)/2

 

(vi) √2 + √5 / √3  

The Rationalising factor of the denominator is  √3.  

= [(√2 + √5) × √3] / √3 × √3

= [√2 × √3 + √5 × √3]/3

= (√6 + √15) /3

 

 

(vii) 3√2/√5

The Rationalising factor of the denominator is √5.  

= (3√2 × √5 )/(√5 × √5)

= 3√10/5

 

HOPE THIS ANSWER WILL HELP YOU…..

 

Some questions of this chapter :

Express each one of the following with rational denominator:

(i) 1/ 3+√2 (ii)1/√6 - √5 (iii) 16/ √41 - 5

(iv)30/ 5√3 - 3√5 (v) 1/ 2√5 - √3 (vi)√3 + 1 / 2√2 - √3 (vii)6 - 4√2 / 6 + 4√2 (viii) 3√2 + 1 / 2√5 - 3 (ix) b² / √a² + b² + a

https://brainly.in/question/15897352

Rationalies the denominator and simplify : (i) √3 - √2 / √3 + √2 (ii)5 + 2√3 / 7+ 4√3 (iii) 1+√2/ 3-2√2, (iv)2√6 - √5 / 3√5 - 2√6 (v)4√3 + 5√2 / √48 + √18, (vi)2√3 - √5 / 2√2 + 3√3

https://brainly.in/question/15897355

Answer 2

Answer:

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