Rationalise the denominator of each of the following
Answers
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Rationalise:
On Rationalise the term denominator
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Step-by-step explanation:
Given:-
(3-2√2)/(3+2√2)
To find:-
Rationalising the denominator ?
Solution:-
Given that
(3-2√2)/(3+2√2)
Denominator = 3+2√2
We know that
Rationalising factor of a+√b = a-√b
Rationalising factor of 3+2√2 = 3-2√2
On Rationalising the denominator then
=> [(3-2√2)/(3+2√2)]×[(3-2√2)/(3+2√2)]
=> [(3-2√2)(3-2√2)]×[(3+2√2)(3-2√2)]
=> (3-2√2)^2/[(3+2√2)(3-2√2)]
We know that
(a+b)(a-b)=a^2-b^2
Where a = 3 and b=2√2
=> (3-2√2)^2/[(3)^2-(2√2)^2]
=> (3-2√2)^2/(9-8)
=>(3-2√2)^2/1
=>(3-2√2)^2
It is in the form of (a-b)^2
Where a = 3 and b=2√2
We know that
(a-b)^2 = a^2-2ab+b^2
=> (3-2√2)^2
=> 3^2 - 2 (3)(2√2) +(2√2)^2
=> 9-12√2+8
=> 17-12√2
(3-2√2)/(3+2√2) = 17-12√2
Answer:-
(3-2√2)/(3+2√2) = 17-12√2
Used formulae:-
- Rationalising factor of a+√b = a-√b
- (a+b)(a-b)=a^2-b^2
- (a-b)^2 = a^2-2ab+b^2
Rationalising factor:-
The product of two irrational numbers is a rational number then each irrational is called a Rationalising factor of each other.