Math, asked by amru2, 1 year ago

rationalise the denominator of
 7 \div 3 \sqrt3 - 2 \sqrt{3} ]{?}

Answers

Answered by sravan29
1
Rationalize the denominator:
3
2
6

3
(
6
+
3
6
+
3
)
​√
​6

​​ −√
​3

​​

​3√
​2

​​
​​ (
​√
​6

​​ +√
​3

​​

​√
​6

​​ +√
​3

​​
​​ )
6
3
+
3
6
6
2

3
2

3
3

6
​√
​6

​​
​2
​​ −√
​3

​​
​2
​​

​6√
​3

​​ +3√
​6

​​
​​ −
​3−√
​6

​​

​3
​​

2 Factor out the common term
3
3
3
(
2
3
+
6
)
6
2

3
2

3
3

6
​√
​6

​​
​2
​​ −√
​3

​​
​2
​​

​3(2√
​3

​​ +√
​6

​​ )
​​ −
​3−√
​6

​​

​3
​​

3 Use this rule:
x
2
=
x

​x

​​
​2
​​ =x
3
(
2
3
+
6
)
6

3
2

3
3

6
​6−√
​3

​​
​2
​​

​3(2√
​3

​​ +√
​6

​​ )
​​ −
​3−√
​6

​​

​3
​​

4 Use this rule:
x
2
=
x

​x

​​
​2
​​ =x
3
(
2
3
+
6
)
6

3

3
3

6
​6−3

​3(2√
​3

​​ +√
​6

​​ )
​​ −
​3−√
​6

​​

​3
​​

5 Simplify
6

3
6−3 to
3
3
3
(
2
3
+
6
)
3

3
3

6
​3

​3(2√
​3

​​ +√
​6

​​ )
​​ −
​3−√
​6

​​

​3
​​

6 Cancel
3
3
2
3
+
6

3
3

6
2√
​3

​​ +√
​6

​​ −
​3−√
​6

​​

​3
​​

7 Rationalize the denominator:
3
3

6
(
3
+
6
3
+
6
)
​3−√
​6

​​

​3
​​ (
​3+√
​6

​​

​3+√
​6

​​
​​ )
2
3
+
6

9
+
3
6
3
2

6
2
2√
​3

​​ +√
​6

​​ −
​3
​2
​​ −√
​6

​​
​2
​​

​9+3√
​6

​​
​​

8 Factor out the common term
3
3
2
3
+
6

3
(
3
+
6
)
3
2

6
2
2√
​3

​​ +√
​6

​​ −
​3
​2
​​ −√
​6

​​
​2
​​

​3(3+√
​6

​​ )
​​

9 Simplify
3
2
3
​2
​​ to
9
9
2
3
+
6

3
(
3
+
6
)
9

6
2
2√
​3

​​ +√
​6

​​ −
​9−√
​6

​​
​2
​​

​3(3+√
​6

​​ )
​​

10 Use this rule:
x
2
=
x

​x

​​
​2
​​ =x
2
3
+
6

3
(
3
+
6
)
9

6
2√
​3

​​ +√
​6

​​ −
​9−6

​3(3+√
​6

​​ )
​​

11 Simplify
9

6
9−6 to
3
3
2
3
+
6

3
(
3
+
6
)
3
2√
​3

​​ +√
​6

​​ −
​3

​3(3+√
​6

​​ )
​​

12 Cancel
3
3
2
3
+
6

(
3
+
6
)
2√
​3

​​ +√
​6

​​ −(3+√
​6

​​ )

13 Simplify brackets
2
3
+
6

3

6
2√
​3

​​ +√
​6

​​ −3−√
​6

​​

14 Collect like terms
2
3
+
(
6

6
)

3
2√
​3

​​ +(√
​6

​​ −√
​6

​​ )−3

15 Simplify
2
3

3
2√
​3

​​ −3

Done

amru2: I did not understand
amru2: what
sravan29: Ur welcome mark me please
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