Question

rationalise the denominator of
$\frac{2}{ 3\sqrt{3} }$
​

Answer 1

Step-by-step explanation:

2÷3√3

2×(-3√3)÷3√3(-3√3)

-6√3÷(-27)

6√3÷27

2√3÷9

Answer 2

$\huge\star\:\:{\orange{\underline{\purple{\mathcal{Solution}}}}}$

$\sf\large\underline\red{To\: solve \: this \: problem:-}$

$\frac{2}{3 \sqrt{3} }$

We have to rationalized the denominator , by multiple and divide the complete number by

$\sqrt{3} .$

By so we can eliminate irrational number from denominator , which is the main motive of rationalisation.

So,

$⇒ \frac{2}{3 \sqrt{3} }$

$⇒ \frac{2 \sqrt{3} }{3 \sqrt{3} \sqrt{3} }$

$⇒ \frac{2 \sqrt{3} }{3 { \sqrt{3} }^{2} }$

$⇒ \frac{2 \sqrt{3} }{3 \times 3}$

$⇒ \frac{2 \sqrt{3} }{9}$

Hence verified ✔