Question

Rationalise the denominator of the following .



1

2+√3

ii) 1

√2

iii) 1

3√5

iv) 1

2−√5​

Answer 1

Answer:

Path is used define where the system can find the executables

Answer 2

Answer:

We need to rationalise 71

Multiply numerator and denominator by 7, we get

=(7×71(7)

=77