rationalise the denominator of the following 1/√ 5,√3+√2/√3-√2, 1/√2+1
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• 1 / √5
= 1 / √5 × √5 / √5
= √5 / 5
_____________________________
• ( √3 + √2 ) / ( √3 – √2 )
= ( √3 + √2 ) / ( √3 – √2 ) × ( √3 + √2 ) / ( √3 + √2 )
= ( √3 + √2 )² / [ ( √3 )² – (√2 )² ]
= ( 3 + 2 + 2√6 ) / ( 3 – 2 )
= 5 + 2√6
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• 1 / ( √2 + 1 )
= 1 / ( √2 + 1 ) × ( √2 – 1 ) / ( √2 – 1 )
= ( √2 – 1 ) / [ (√2 )² – ( 1 )² ]
= ( √2 – 1 ) / ( 2 – 1 )
= √2 – 1
______________________________
• 1 / √5
= 1 / √5 × √5 / √5
= √5 / 5
_____________________________
• ( √3 + √2 ) / ( √3 – √2 )
= ( √3 + √2 ) / ( √3 – √2 ) × ( √3 + √2 ) / ( √3 + √2 )
= ( √3 + √2 )² / [ ( √3 )² – (√2 )² ]
= ( 3 + 2 + 2√6 ) / ( 3 – 2 )
= 5 + 2√6
______________________________
• 1 / ( √2 + 1 )
= 1 / ( √2 + 1 ) × ( √2 – 1 ) / ( √2 – 1 )
= ( √2 – 1 ) / [ (√2 )² – ( 1 )² ]
= ( √2 – 1 ) / ( 2 – 1 )
= √2 – 1
______________________________
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Helll friend
Good evening
Your answer is in the attachment
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Good evening
Your answer is in the attachment
I hope it will help you a lot
Thanks
❤❤❤❤❤❤❤❤❤❤❤❤
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swetha50:
you are wrong
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