Question

rationalise the denominator of the following 1 by 3+root 2​

Answer 1

Answer:

We have,

$\frac{1}{3 + \sqrt{2} }$

$= \frac{1(3 - \sqrt{2}) }{(3 + \sqrt{2})(3 - \sqrt{2}) }$

$= \frac{3 - \sqrt{2} }{ {(3)}^{2} - {(\sqrt{2)} }^{2} }$

$= \frac{3 - \sqrt{2} }{9 - 2}$

$= \frac{3 - \sqrt{2} }{7}$

Hence,

rationalised

Answer 2

Answer:

$\tt \huge {\frac{3 - \sqrt{2} }{7}}$

Refer the attachment.