Math, asked by shaun69, 1 year ago

rationalise the denominator of the following 1 / root 5 + root 2

Answers

Answered by saiagarwal707
9

Answer:√5-√2/3


Step-by-step explanation:

1/√5+√2

Let R.F=√5-√2

(1/√5+√2)×(√5-√2/√5-√2)

√5-√2/(√5+√2)(√5-√2)

√5-√2/5-2

√5-√2/3

Answered by gegfhfhbduwobshakdbs
9

 \large \tt AHOY!! \:

 \sf given  :  -  \frac{1}{ \sqrt{5} +  \sqrt{2}  } \\  \\  \sf  =  \frac{1}{ \sqrt{5}  +  \sqrt{2} }  \times  \frac{ \sqrt{5}  -  \sqrt{2} }{ \sqrt{5} -  \sqrt{2}  }  \\  \\  =  \sf \frac{ \sqrt{5} -  \sqrt{2}  }{( \sqrt{5} +  \sqrt{2} )( \sqrt{5}  -  \sqrt{2} ) }  \\  \\  =  \sf \frac{ \sqrt{5}  -  \sqrt{2} }{( { \sqrt{5} )}^{2}  -  {( \sqrt{2} )}^{2} }  \\  \\  =  \frac{ \sqrt{5}  -  \sqrt{2} }{5 - 2} \\  \\  \sf =  \frac{ \sqrt{5}  -  \sqrt{2} }{3}


 \large \tt HOPE  \: THIS  \: HELPS!!

shaun69: thank u because i write this answer for my assignment
gegfhfhbduwobshakdbs: ohh.. wlcm : )
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