Question

rationalise the denominator of the following
18_4-√7​

Answer 1

$\frac{18}{4 - \sqrt{7} } \times \frac{4 + \sqrt{7} }{4 + \sqrt{7} } \\ \\ = > \frac{18(4 + \sqrt{7} )}{ {4}^{2} - { \sqrt{7} }^{2} }$

$= > \frac{72 + 8 \sqrt{7} }{16 - 7} \\ \\ = > \frac{72 + 18 \sqrt{7} }{9} = 8 + 2 \sqrt{7}$

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