Math, asked by parneetsandhu92, 1 year ago

rationalise the denominator of the following ​

Attachments:

Answers

Answered by Anonymous
4

\tt{\frac{2\sqrt{3} }{\sqrt{5} }}

The simplest rationalizing factor = √5 is √5

So, multiply numerator and denominator of the given fraction by √5

\tt{ =\frac{2\sqrt{3} \times \sqrt{5} }{\sqrt{5} \times \sqrt{5}}}

\tt{=\frac{2\sqrt{3 \times 5} }{{(\sqrt{5})}^{2} }}

\tt{=\frac{2\sqrt{15} }{5} }

\tt{=\frac{2\sqrt{15} }{5} }

\boxed{\sf{\large{\frac{2\sqrt{3} }{\sqrt{5} } = \frac{2\sqrt{15} }{5}}}}}

Answered by DhanyaDA
5

hope the answer helps u

Attachments:
Similar questions