Math, asked by sahajsingh120907, 28 days ago

rationalise the denominator of the following:-
i) 5√7/√3
ii) 1/√5+√2

Answers

Answered by Subhajitz
3

Answer:

i)

\frac{5 \sqrt{21} }{3}

ii)

\frac{5 -  \sqrt{2} }{23}

Step-by-step explanation:

i)

 \frac{5 \sqrt{7} }{ \sqrt{3} }  =  \frac{5 \sqrt{7} }{ \sqrt{3} } \times  \frac{ \sqrt{3} }{ \sqrt{3} }  \\  =  \frac{5 \sqrt{21} }{3}

ii)

 \frac{1}{5 +  \sqrt{2} }  =  \frac{1}{5 +  \sqrt{2} } \times \frac{5 -  \sqrt{2} }{5 -  \sqrt{2} }  \\   = \frac{5 -  \sqrt{2} }{ {(5)}^{2} -  {( \sqrt{2}) }^{2}  }   \\ =  \frac{5 -  \sqrt{2} }{25 - 2}  \\  =  \frac{5 -  \sqrt{2} }{23}

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