Question

Rationalise the denominator of the following. please solve these questions !!​

Answer 1

$\Huge\bf\maltese{\underline{\green{Answer°᭄}}}\maltese$

$\implies$$\large\bf{\underline{\red{VERIFIED✔}}}$

$\bf\huge{\purple{╔════════♡︎═╗}}$

______________________

1) = 3/4√5x4√5/4/5

= 12√5/16x5

=12√5/80

______________________

2) In Attachment.

______________________

3) $\frac{3}{4 - \sqrt{3} } \times \frac{4 + \sqrt{3} }{4 + \sqrt{3} } \\= \frac{12 + 3 \sqrt{3} }{16 - 3} \\= \frac{12 + 3 \sqrt{3} }{13}$

______________________

4) =1/7+3√2× 7-3√2/7-3√2

=7-3√2/ (7+3√2)(7-3√2)

=7-3√2/(7)^2-(3-√2)^2

=7-3√2/49-18

=7-3√2/31

______________________

5)16/(root41 - 5)

=16(root41+5)/[(root 41-5)(root41+5)]

=[16(root41+5)]/[(root41)^2 -(5)^2]

=[16(root41+5)]/(41-25) =16(root41+5]/16

=root41+5

______________________

6) 1-√7-√6x√7+√6-√7x√6

√7+√6 +√7^2-√6^2 ((a+b)(a-b)=a^2-b^2)

Step-by-step explanation:

√7+√6-7-6

√7+√6-1

=√7+√6

______________________

7) In Attachment

______________________

8) (√3+√2)/(√3-√2)

=(√3+√2)/(√3-√2)x√3+√2/√3+√2

=(√3+√2)(√3+√2)/(√3-√2)(√3+√2)

=(√3+√2)²/(√3²-√2²)

=[√3²+√2²+2(√3)(√2)]/3-2

=(3+2+2√6)/1

=5+2√6

______________________

$\bf\huge{\pink{╚═♡︎════════╝}}$

$\boxed{I \:Hope\: it's \:Helpful}$

${\sf{\bf{\blue{@ℐᴛz ᴅɪɴᴜ࿐}}}}$

Answer 2

Step-by-step explanation:

$Answer$

$= \: {4}^{2} \times 3 \times \frac{4}{8}$