Question

rationalise the denominator of the following root 6 by root 3 minus root 2​

Answer 1

Step-by-step explanation:

$\frac{ \sqrt{6} }{ \sqrt{3 - {2} } }$

$\frac{ \sqrt{6 \times 3 + 2} }{ {3}^{2} + {2}^{2} }$

$\frac{ \sqrt{6 \times 3 + 2} }{ {3}^{2} + {2}^{2} }$

$\frac{ \sqrt{6 \times 3 + 2} }{13 }$

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