Question

rationalise the denominator of the following
$\sqrt{2} + \sqrt{5} \div \sqrt{3}$

$1 \div 2 \sqrt{5}$
​

Answer 1

• Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Given:

• $\frac{ \sqrt{2} + \sqrt{5} }{ \sqrt{3} }$

★ Rationalising the denominator ★

$= > \frac{ \sqrt{2 } + \sqrt{5} }{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} }$

$= > \frac{ \sqrt{6} + \sqrt{15} }{ \sqrt{3} }$

Second =

$\frac{1}{{2 \sqrt{5} } }$

★ Rationalising the denominator ★

$= > \frac{1}{2 \sqrt{5} } \times \frac{2 \sqrt{5} }{2 \sqrt{5} }$

$= > \frac{2 \sqrt{5} }{ {2}^{2} \times \sqrt{25} }$

$= > \frac{2 \sqrt{5} }{4 \times 5}$

$= > \frac{2 \sqrt{5} }{20}$