Math, asked by ayushnegi9690, 9 months ago

Rationalise the denominator of these

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Answered by sudarshankatare4
0

Answer:

I dont know the answer Mark me brainiest

Answered by arunyadav1973
0

Solution :—

1). \:  \:  \:  \:  \:  \:  \:  \:  \frac{3}{ \sqrt{7} -  \sqrt{5}  }  \\ rationlize \: the \: denominator \\  \frac{3( \sqrt{7} +  \sqrt{5})  }{( \sqrt{7} -  \sqrt{5} )( \sqrt{7}   +  \sqrt{5} }  \\  =  \frac{3 \sqrt{7} + 3 \sqrt{5}  }{  { (\sqrt{7} )}^{2}  -  {( \sqrt{5} )}^{2} }  \\  =  \frac{3 \sqrt{7}  + 3 \sqrt{5} }{7 - 5}  \\  =  \frac{3 \sqrt{7}  + 3 \sqrt{5} }{2}

2). \:  \:  \:  \:  \:  \frac{1}{ \sqrt{8}  +  \sqrt{3} }  \\ rationalize \: the \: denominator \\  \frac{1( \sqrt{8}  -  \sqrt{3} )}{( \sqrt{8}  +  \sqrt{3} )( \sqrt{8} -  \sqrt{3}  )}  \\  =  \frac{ \sqrt{8}  -  \sqrt{3} }{ {( \sqrt{8} )}^{2}  -   {( \sqrt{3} )}^{2}  }  \\  =  \frac{ \sqrt{8}  -  \sqrt{3} }{8 - 3}  \\   =  \frac{ \sqrt{8}  -  \sqrt{3} }{5}

Thanks for the question bro ❤️❣️✌️✍️

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