Rationalise the denominator of unroot 5 / 2-root7
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Answered by
0
Answer:
- (2√5 + √35) / 3 or (-2√5 - √35) / 3
Step-by-step explanation:
√5/2-√7 = √5 * (2+√7) / (2-√7) * (2+√7 )
= ( 2*√5 + √5 *√7) / 2² - (√7)² { (a+b) (a-b) = a² - b² }
= (2√5 + √35) / 4 - 7 = (2√5 + √35) / - 3
= - (2√5 + √35) / 3
Answered by
1
Answer:
- (2√5 + √35) / 3 or (-2√5 - √35) / 3
Step-by-step explanation:
√5/2-√7 = √5 * (2+√7) / (2-√7) * (2+√7 )
= ( 2*√5 + √5 *√7) / 2² - (√7)² { (a+b) (a-b) = a² - b² }
= (2√5 + √35) / 4 - 7 = (2√5 + √35) / - 3
= - (2√5 + √35) / 3
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