Question

rationalise the denominator please​

Answer 1

Answer:

hope it will help you friend

Answer 2

ANSWER:

$7 - 4 \sqrt{3}$

EXPLANATION:

$\frac{1}{7 + 4 \sqrt{3} }$

$= \frac{1}{7 + 4 \sqrt{3} } \times \frac{7 - 4 \sqrt{3} }{7 - 4 \sqrt{3} }$

$= \frac{1(7 - 4 \sqrt{3} )}{(7 + 4 \sqrt{3} )(7 - 4 \sqrt{3} )}$

$= \frac{7 - 4 \sqrt{3} }{ {(7)}^{2} - {(4\sqrt{3} )}^{2} }$

$= \frac{7 - 4 \sqrt{3} }{49 - (16)(3)}$

$= \frac{7 - 4 \sqrt{3} }{49 - 48}$

$= \frac{7 - 4 \sqrt{3} }{1}$

$= 7 - 4 \sqrt{3}$

I hope it helps you. Please mark me as BRAINLIEST if you like.