Math, asked by bhatia11ananya, 3 months ago

rationalise the denominator
please explain your answer​

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Answered by rainha
1

Answer:

 \frac{1}{1 +  \sqrt{2}  +  \sqrt{3}  }  \times  \frac{1 +  \sqrt{2}  -  \sqrt{3} }{1 +  \sqrt{2}  -  \sqrt{3} }  =  \frac{1 +  \sqrt{2}   - \sqrt{3} }{ {(1 +  \sqrt{2}) }^{2}  - 3}

 =  \frac{1 +  \sqrt{2}  -  \sqrt{3} }{1 + 2 + 2 \sqrt{2} - 3 }

 =  \frac{1 +  \sqrt{2} -  \sqrt{3}  }{2 \sqrt{2} }

 =  \frac{1 +  \sqrt{2} -  \sqrt{3}  }{2 \sqrt{2} }  \times  \frac{ \sqrt{2} }{ \sqrt{2} }

 =  \frac{\sqrt{2}  + 2 -  \sqrt{6}  }{4}

Answered by hrurudyh
0

Answer:

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