rationalise the denominator please full explanation bta do koi
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Step-by-step explanation:
√3/5+2√3 =√3×5-2√3/5+2√3×5-2√3
=5√3-2√3×√3/(5) ²-(√2) ²
=5√3-6/(5) ²-(√2) ²
=5√3-6/25-2
=5√3-6/23
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