Math, asked by andal19anjali, 2 months ago

rationalise the denominator
please give me correct answer of this question if you give correct answer I will mark you as brain list
it is very very urgent ​

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Answers

Answered by riddhiacharya285
4

Answer:

hope it helps..

First each should be rationised and then added.

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Answered by NJD38
1

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\frac{1}{1+\sqrt{2} } +\frac{1}{\sqrt{2}+\sqrt{3}  } \\\\=\frac{1(1-\sqrt{2} )}{(1+\sqrt{2})(1-\sqrt{2})  } +\frac{1(\sqrt{2}-\sqrt{3} )}{(\sqrt{2}+ \sqrt{3})(\sqrt{2}- \sqrt{3})  } \\\\=\frac{1-\sqrt{2} }{1-2}+\frac{\sqrt{2}- \sqrt{3} }{2-3} \;\;\;\;\;\;\;\;\;\;\;[(a+b)(a-b)=a^{2} -b^{2} ] \\\\=\frac{1-\sqrt{2} }{(-1)} +\frac{\sqrt{2}- \sqrt{3} }{(-1)} \\\\=-(1-\sqrt{2} )-(\sqrt{2}- \sqrt{3})\\\\=-1+\sqrt{2}-\sqrt{2}   +\sqrt{3}\\\\=\sqrt{3}-1

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