Math, asked by andal19anjali, 5 hours ago

rationalise the denominator
please give me correct answer of this question if you give correct answer I will mark you as brain list
it is very very urgent ​

Attachments:

Answers

Answered by riddhiacharya285
4

Answer:

hope it helps..

First each should be rationised and then added.

Attachments:
Answered by NJD38
1

\huge{\overbrace{\underbrace{\texttt{\blue{A}\red{N}\blue{S}\red{W}\blue{E}\red{R} } } } }

\frac{1}{1+\sqrt{2} } +\frac{1}{\sqrt{2}+\sqrt{3}  } \\\\=\frac{1(1-\sqrt{2} )}{(1+\sqrt{2})(1-\sqrt{2})  } +\frac{1(\sqrt{2}-\sqrt{3} )}{(\sqrt{2}+ \sqrt{3})(\sqrt{2}- \sqrt{3})  } \\\\=\frac{1-\sqrt{2} }{1-2}+\frac{\sqrt{2}- \sqrt{3} }{2-3} \;\;\;\;\;\;\;\;\;\;\;[(a+b)(a-b)=a^{2} -b^{2} ] \\\\=\frac{1-\sqrt{2} }{(-1)} +\frac{\sqrt{2}- \sqrt{3} }{(-1)} \\\\=-(1-\sqrt{2} )-(\sqrt{2}- \sqrt{3})\\\\=-1+\sqrt{2}-\sqrt{2}   +\sqrt{3}\\\\=\sqrt{3}-1

\large{\underbrace{\mathfrak{Hope \: it \: Helps. . .}}}

\large{\boxed{\mathcal{\red{DROP \; A \; HEART!!!} } } }

\large{\boxed{\mathcal{\red{MARK \; AS \; BRAINLIEST!} } } }

\large{\texttt{@NJD} }

Similar questions