Question

Rationalise the denominator रूट 7 upon 2 रूट 3 ​

Answer 1

Answer:

$\frac{ \sqrt{7} }{2 \sqrt{3} } \\ = \frac{ \sqrt{7} }{2 \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } \\ = \frac{ \sqrt{7} \times \sqrt{3} }{2 \sqrt{3} \times \sqrt{3} } \\ = \frac{ \sqrt{7 \times 3} }{2 \times 3} \\ = \frac{ \sqrt{21} }{6}$