Question

Rationalise the denominator root 6 by root 3 - root 2​

Answer 1

Answer:

$\frac{ \sqrt{6} }{ \sqrt{3} } - \sqrt{2} = \frac{ \sqrt{6} }{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } - \sqrt{2}$

$= \frac{3 \sqrt{2} }{3} - \sqrt{2}$

$= \sqrt{2 } - \sqrt{2} = 0$