Math, asked by tripura90, 19 days ago

Rationalise the denominator root 7 + root 2 by root 7 - root 2

Answers

Answered by aashigngwr
43

Answer:

this is the answer.

Step-by-step explanation:

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Answered by Anonymous
41

Answer:

Question:

  • { \sf{Rationalize \:   :  \frac{ \sqrt{7 }  +  \sqrt{2} }{ \sqrt{7} -  \sqrt{2}  }  }} \\

Solution:

: { \implies{ \sf{ \frac{ \sqrt{7} +  \sqrt{2}  }{ \sqrt{7}  -  \sqrt{2} } }}} \\  \\ : { \implies{ \sf{ \frac{ \sqrt{7}  +  \sqrt{2} }{ \sqrt{7}  -  \sqrt{2} } \times  \frac{ \sqrt{7 } +  \sqrt{2}  }{ \sqrt{7}  +  \sqrt{2} }  }}} \\  \\ : { \implies{ \sf{  \frac{ {( \sqrt{7} +  \sqrt{2} ) }^{2} }{ { \sqrt{(7)} }^{2}  -  { \sqrt{(2)} }^{2} } }}} \\  \\ : { \implies{ \sf{ \frac{ ({ \sqrt{7}) }^{2} +  {( \sqrt{2} )}^{2} + 2( \sqrt{7} )( \sqrt{2}  ) }{7 - 2} }}} \\  \\ : { \implies{ \sf{ \frac{7 + 2 + 2 \sqrt{14} }{5} }}} \\  \\ : { \implies{ \sf{ \frac{9 + 2 \sqrt{14} }{5} }}}

{ \therefore{ \sf{  \frac{ \sqrt{7 }  +  \sqrt{2} }{ \sqrt{7} -  \sqrt{2}  }  =  \frac{9 + 2 \sqrt{14} }{5}  }}} \\

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