Math, asked by mahisriguntur, 5 hours ago

rationalise the denominator
root 7 - root 5 / root 7 +root 5​

Answers

Answered by NightSparkle
6

Solutions :-

\red{ \boxed{\sf{ \frac{4 + 3 \sqrt{5} }{4 - 3 \sqrt{5} }  =  \:  \frac{(4 + 3 \sqrt{5} )(4 + 3 \sqrt{5} )}{(4 - 3 \sqrt{5})(4 + 3  \sqrt{5} ) } }}}

\red{ \boxed{{ =  \frac{16 + 45 + 24 \sqrt{5} }{16 - 45}  =  -  \frac{61}{29} -  \frac{24}{29}   \sqrt{5} }}}

Happy Learning !!

Answered by OoAryanKingoO78
3

Answer:

Question:-

Rationalise the denominator

root 7 - root 5 / root 7 +root 5

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Solutions :-

\purple{ \boxed{\tt{ \frac{4 + 3 \sqrt{5} }{4 - 3 \sqrt{5} }  =  \:  \frac{(4 + 3 \sqrt{5} )(4 + 3 \sqrt{5} )}{(4 - 3 \sqrt{5})(4 + 3  \sqrt{5} ) } }}}

\purple{ \boxed{{ =  \frac{16 + 45 + 24 \sqrt{5} }{16 - 45}  =  -  \frac{61}{29} -  \frac{24}{29}   \sqrt{5} }}}

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\boxed{\underline{\tt \red{Thank \: you}}}

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