Math, asked by reddy27465, 7 months ago

rationalise the denominator root3/5+2root3​

Answers

Answered by MissKalliste
6

Answer:

\boxed{\frac {5 \sqrt{3} - 6}{13}}

Step-by-step explanation:

Check attachment for more explanation.

Identity used :

  • Here, only one identity is used : - = (a+b) (a-b)

How to rationalize denominator?

  • To rationalize denominator, we just have to change the signs i.e. + or -.
  • We have to write it in the opposite side of the sum.

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Answered by Anonymous
2

Rationalalise the denominator :

 \dfrac{ \sqrt{3} }{5 + 2 \sqrt{3} }

=>  \dfrac{ \sqrt{3} }{5 + 2 \sqrt{3} }   \times  \dfrac{5 - 2 \sqrt{3} }{5 - 2 \sqrt{3} }

Using the identity : (a + b)(a - b) = a² - b²

=> \dfrac{ \sqrt{3} (5 - 2 \sqrt{3}) }{ {(5)}^{2}  -  {(2 \sqrt{3}) }^{2} }

=>  \dfrac{5 \sqrt{3} - 6 }{25 - 12}

=>  \dfrac{5 \sqrt{3} - 6 }{13}

To rationalize a denominator, we multiply both top and bottom by changing the signs( '+' or '-' ) of the denominator.

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