Question

Rationalise the denominator square
3-7√3/4+2√5

Answer 1

Answer:

Step-by-step explanation:

$\frac{3-7\sqrt{3}}{4+2\sqrt{5}}\times\frac{4-2\sqrt{5}}{4-2\sqrt{5}}\\\frac{12-6\sqrt{5}-28\sqrt{3}+14\sqrt{15}}{16-20}\\\frac{3\sqrt{5}+\sqrt{3}-14\sqrt{15}-12}{4}\\\frac{6\sqrt{5}+14\sqrt{3}-7\sqrt{15}-6}{2}$