Question

rationalise the denominator
$1 \div \sqrt{3} + \sqrt{2} \: and \: evalute \: by \: taking \sqrt{3} = 1.732 \: and \sqrt{2} = 1.414$
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Answer 1

Answer:

0.318

Step-by-step explanation:

$\frac{1}{( \sqrt{3} + \sqrt{2} ) } \times \frac{( \sqrt{3} - \sqrt{2}) }{ (\sqrt{ 3} - \sqrt{2} )} \\ = \frac{ \sqrt{3} - \sqrt{2} }{ {( \sqrt{3}) }^{2} - {( \sqrt{2} )}^{2} } \\ = \frac{ \sqrt{3} - \sqrt{2} }{3 - 2} \\ = \sqrt{3} - \sqrt{2} \\ = 1.732 - 1.414 \\ = 0.318$