Question

Rationalise the denominator
$3 + \sqrt{2} \: divide \: by \: 3 - \sqrt{2}$
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Answer 1

$\huge\mathbb{A~N~S~W~E~R}$

$= \frac{3 + \sqrt{2} }{3 - \sqrt{2} } \\ \\ = \frac{3 + \sqrt{2} }{3 - \sqrt{2} } \times \frac{3 + \sqrt{2} }{3 + \sqrt{2} } \\ \\ = \frac{ {(3 + \sqrt{2} )}^{2} }{9 - 2} \\ \\ = \frac{9 + 6 \sqrt{2} + 2}{7} \\ \\ = \frac{11 + 6 \sqrt{2} }{7}$

${\huge\color{Red}{Answer~is~\frac{11+6\sqrt{2}}{7} }}$

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Answer 2

$\mathbb{\red{\huge{HEY\:MATE}}}$

$\boxed{HERE\:IS\:YOUR\:ANSWER}$

$\mathfrak{\green{ANSWER:}}$

Please refer to the given attachment