Question

Rationalise the denominator

$\frac{1}{ \sqrt{7} + \sqrt{6} }$

Answer 1

Hola Mate!!

Your answer :-

$= > \frac{1}{ \sqrt{7} + \sqrt{6} } \\ \\ = > \frac{1}{ \sqrt{7} + \sqrt{6} } \times \frac{ \sqrt{7} - \sqrt{6} }{ \sqrt{7} - \sqrt{6} } \\ \\ = > \frac{ \sqrt{7} - \sqrt{6} }{( { \sqrt{7} )}^{2} - {( \sqrt{6} )}^{2} } \\ \\ = > \frac{ \sqrt{7} - \sqrt{6} }{7 - 6} \\ \\ = > \frac{ \sqrt{7} - \sqrt{6} }{1} \\ \\ = > \sqrt{7} - \sqrt{6}$

☆ Hope it helps ☆

Answer 2

Hey

Here is your answer,

= 1/√7+√6 x √7-√6 / √7-√6
= √7-√6/(√7)^2 - (√6)^2
= √7-√6 / 7-6
= √7-√6 /1
= √7-√6

Hope it helps you!