Question

rationalise the denominator
$\frac{4}{3 + \sqrt{3} }$
answer should be
$\frac{6 - 2 \sqrt{3} }{3}$
according to book​

Answer 1

Answer:

$\frac{6 - 2 \sqrt{3} }{3}$

Step-by-step explanation:

$\frac{4}{3 + \sqrt{3} } \times \: \frac{3 - \sqrt{3} }{3 - \sqrt{3} } = \: \frac{12 - 4 \sqrt{3} }{9 - 3} \\ \frac{12 - 4 \sqrt{3} }{6} = \: \frac{2(6 - 2 \sqrt{3} )}{6} = \frac{6 - 2 \sqrt{3} }{3}$