Math, asked by lubuhmygreatbro, 1 year ago

Rationalise the denominator

 \frac{ \sqrt{5} }{ \sqrt{5}  -  \sqrt{3} }

Answers

Answered by Anonymous
14
Hola Mate!!

Your answer :-

 =  >  \frac{ \sqrt{5} }{ \sqrt{5} -  \sqrt{3}  }  \\  \\  =  >  \frac{ \sqrt{5} }{ \sqrt{5}  -  \sqrt{3} }  \times   \frac{ \sqrt{5} +  \sqrt{3}  }{ \sqrt{5}  +  \sqrt{3} }  \\  \\  =  >   \frac{ \sqrt{5} ( \sqrt{5}  +  \sqrt{3}) }{( { \sqrt{5} )}^{2} -  ({ \sqrt{3} )}^{2}  }  \\  \\  =  >  \frac{5 +  \sqrt{15} }{5 - 3}  \\  \\  =  >  \frac{ 5 +  \sqrt{15}  }{2}

☆ Hope it helps ☆
Answered by Anonymous
11
Hey !

____________________________________________

↪√ 5 / √ 5 - √ 3

↪√ 5 / √ 5 - √ 3 ( √ 5 + √ 3 / √ 5 + √3 )

↪ Using the identity in denominator !!

↪ (a + b) (a - b) = a ^2 - b ^2

↪√ 5 ( √ 5 + √ 3 ) / √ 5 ^ 2 - √ 3 ^2

↪5 + √ 15 / 5 - 3

↪ 5 + √ 15 / 2

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lubuhmygreatbro: dusra way se krte didi
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lubuhmygreatbro: jese dipul ne kiya
Anonymous: Yep jih :)
Anonymous: uff!! ja arsh tenu kinni problem aandi aa
Anonymous: simple jehe question ne
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