Math, asked by rethik43, 11 months ago

rationalise the denominator3+√2/3-√2+6-√2/√6+√3​

Answers

Answered by Gautamkumr
1

=3+√2/3-√2+6-√2/√6+√3

=(3+√2/3-√2 ×3+√2/3+√2) +(6-√2/√6+√3 ×√6-√3/√6-√3 )

=(9+6√2/9-2)+(36-12√2/6-3)

=9+6√2/7 + 36-12√2/3

=27+18√2 + 252-84√2/21

=279-66√2/21

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