Math, asked by balasahebaaba76, 3 days ago

rationalise the denominators: ¹___ 3√5+2√2​

Answers

Answered by eeepathshala
0

Answer:

 \frac{1}{3 \sqrt{5} + 2 \sqrt{2}  } \\  =   \frac{1 \times(3\sqrt{5}  -  2 \sqrt{2}) }{(3 \sqrt{5} + 2 \sqrt{2}) \times (3 \sqrt{5}  -  2 \sqrt{2})} \\  =  \frac{3 \sqrt{5 }  - 2 \sqrt{2} }{ {(3 \sqrt{5}) }^{2} -  {(2 \sqrt{2} )}^{2}  }  \\  =  \frac{3 \sqrt{5} - 2 \sqrt{2}  }{9 \times 5 - 4 \times 2}  \\  =  \frac{3 \sqrt{5}  - 2 \sqrt{2} }{45 - 8}  \\  =  \frac{3 \sqrt{5} - 2 \sqrt{2}  }{37}

Step-by-step explanation:

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