Question

Rationalise the denominators
1/root 7-root 6​

Answer 1

Step-by-step explanation:

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Answer 2

To Find :

We have to rationalise the denominator of $\sf{ \dfrac{1}{\sqrt{7} - \sqrt{6}}}$

Explanation :

As, we have to rationalise the denominator. So, we have to follow the given below steps :

• Firstly, for rationalising we will saw in numerator that there is root or not in the denominator. If there is root then only we will rationalise the denominator.
• We will multiply the number which is in denominator by numerator and denominator by changing the last sign. If there is only one sign then we will not change the sign
• Them, we will simplify the numerator and denominator.

$\sf{\dashrightarrow \dfrac{1}{ \sqrt{7} - \sqrt{6}} \times \dfrac{ \sqrt{7} + \sqrt{6}}{ \sqrt{7} - \sqrt{6}}} \\ \\ \sf{\dashrightarrow \dfrac{ \sqrt{7} + \sqrt{6}}{(\sqrt{7})^2 - (\sqrt{6})^2}} \\ \\ \sf{\dashrightarrow \dfrac{ \sqrt{7} + \sqrt{6}}{7 - 6}} \\ \\ \sf{\dashrightarrow \sqrt{7} + \sqrt{6}} \\ \\ \large{\star{\underline{\boxed{\sf{\sqrt{7} + \sqrt{6}}}}}}$