rationalise the denominators of 1/1-√7 and plz see the image plz help friends
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hope its help you.....
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Gandharva8:
when you have taken - upwards the above value should come in bracket....numerator should be -1 -√7
the answer is wrong
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1/1-√7*(1+√7)/(1+√7)
(1+√7)/(1-√7)(1+√7). [(a+b)(a-b)=a^2-b^2]
(1+√7)/(1^2)-(√7)^2
(1+√7)/(1-7)
(1+√7)/-6
(-1-√7)/6
(1+√7)/(1-√7)(1+√7). [(a+b)(a-b)=a^2-b^2]
(1+√7)/(1^2)-(√7)^2
(1+√7)/(1-7)
(1+√7)/-6
(-1-√7)/6
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