Question

Rationalise the denominators of:
$\frac{ \sqrt{2} }{1 + \sqrt{3} }$
Please answer it fast

Answer 1

Hey user

Here is your answer :-

$\frac{ \sqrt{2} }{1 + \sqrt{3} } \\ \\ \frac{ \sqrt{2}(1 - \sqrt{3}) }{(1 + \sqrt{3})(1 - \sqrt{3}) } \\ \\ \frac{ \sqrt{2} - \sqrt{6} }{ {1}^{2} - { \sqrt{3} }^{2} } \\ \\ \frac{ \sqrt{2} - \sqrt{6} }{1 - 3} \\ \\ \frac{ \sqrt{2} - \sqrt{6} }{ - 2} \\ \\ \frac{ \sqrt{6} - \sqrt{2} }{2}$

Thank you.