Math, asked by sanmitha2712, 1 year ago

Rationalise the denominators of:
 \frac{ \sqrt{2} }{1 +  \sqrt{3} }
Please answer it fast

Answers

Answered by Thatsomeone
14
Hey user

Here is your answer :-

 \frac{ \sqrt{2} }{1 +  \sqrt{3} }  \\  \\  \frac{ \sqrt{2}(1 -  \sqrt{3})  }{(1 +  \sqrt{3})(1 -  \sqrt{3})  }  \\  \\  \frac{ \sqrt{2} -  \sqrt{6}  }{ {1}^{2} -  { \sqrt{3} }^{2}  }  \\  \\  \frac{ \sqrt{2}   -   \sqrt{6} }{1 -  3}  \\  \\  \frac{ \sqrt{2} -  \sqrt{6}  }{ - 2}  \\  \\  \frac{ \sqrt{6} -  \sqrt{2}  }{2}

Thank you.

sanmitha2712: Thank u
Thatsomeone: no need
Similar questions