Math, asked by pranjitrongchan047, 30 days ago

Rationalise the denominators (viii)
2√3 - 3√ 2 ___by_____ 3√2 + 2√3​

Answers

Answered by sandy1816
1

 =  \frac{2 \sqrt{3}  - 3 \sqrt{2} }{2\sqrt{3} + 3 \sqrt{2}  }  \\  =  \frac{2 \sqrt{3} - 3 \sqrt{2}  }{2 \sqrt{3}  + 3 \sqrt{2} }  \times  \frac{2 \sqrt{3} - 3 \sqrt{2}  }{2 \sqrt{3} - 3 \sqrt{2}  }  \\  =  \frac{ ({2 \sqrt{3}  - 3 \sqrt{2} })^{2} }{( {2 \sqrt{3} })^{2}  - ( {3 \sqrt{2} })^{2} }  \\  =  \frac{12 + 18 - 12 \sqrt{6} }{12 - 18}  \\  =   \frac{30 - 12 \sqrt{6} }{ - 6}  \\  =  - 5 + 2 \sqrt{6}

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