Math, asked by gsch, 1 year ago

rationalise the dinominator √2\√2+√3-√5

Answers

Answered by skh2
1
Hello,

Please refer to the above photo for the used process

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Answered by Rupika12345
0

 \frac{ \sqrt{2} }{ \sqrt{2}  +  \sqrt{3} -  \sqrt{5}  }  \times  \frac{ \sqrt{2} +  \sqrt{3}  -  \sqrt{5}  }{ \sqrt{2} +  \sqrt{3}  -  \sqrt{5}  }


 \frac{2 +  \sqrt{6} -  \sqrt{10}  }{2 + 3 - 5} =  \frac{2 +  \sqrt{6} -  \sqrt{10} }{0}   = 0
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