Question

rationalise the dinominator 3/√7-√2​

Answer 1

Answer:

rationalise the dinominator 3/√7-√2

Answer 2

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$</u></em></strong><strong><em><u>\</u></em></strong><strong><em><u>t</u></em></strong><strong><em><u>t</u></em></strong><strong><em><u> </u></em></strong><strong><em><u>= > \frac{3}{ \sqrt{7} - \sqrt{2} }$

By rationalising the denominator.....we get ;

$</u><u> </u><u>\</u><u>t</u><u>t</u><u> </u><u> = > \frac{3}{ \sqrt{7} - \sqrt{2} } \times \frac{ \sqrt{7} + \sqrt{2} }{ \sqrt{7} + \sqrt{2} }$

$</u><u>\</u><u>t</u><u>t</u><u> </u><u>= > \frac{3( \sqrt{7} + \sqrt{2}) }{( \sqrt{7} ) {}^{2} - ( \sqrt{2} ) {}^{2} }$

$</u><u> </u><u>\</u><u>t</u><u>t</u><u> </u><u> = > \frac{3( \sqrt{7} + \sqrt{2}) }{7 - 2}$

$</u><u> </u><u>\</u><u>t</u><u>t</u><u> = > \frac{3}{5} ( \sqrt{7 } + \sqrt{2} )$

Hope it's Helpful....:)