rationalise the dinominator
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√3-1/√3+1
= (√3-1)(√3-1)/(√3+1)x (√3-1)
=3- √3 -√3+1 / 3-1
= 4-√6/2
= 4 - 2√3 / 2
= 2(2-√3)/2
= 2-√3..........
= (√3-1)(√3-1)/(√3+1)x (√3-1)
=3- √3 -√3+1 / 3-1
= 4-√6/2
= 4 - 2√3 / 2
= 2(2-√3)/2
= 2-√3..........
chocopiee:
ohkkk.....
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hope it helps!
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