Question

Rationalise the dinominator
urgent answer plz no spamming​

Answer 1

Answer:

$\frac{ - 5 \sqrt{3} - 5 \sqrt{5} }{2}$

Step-by-step explanation:

$\frac{5}{ \sqrt{3} - \sqrt{5} }$

Now, in order to rationalize the denominator, we need to multiply by the opposite pair i.e., √3+√5 in numerator and denominator....

$= \frac{5}{ \sqrt{3} - \sqrt{5} } \times \frac{ \sqrt{3} + \sqrt{5} }{\sqrt{3} + \sqrt{5} }$

$= \frac{ 5( \sqrt{3} + \sqrt{5} )}{ { (\sqrt{3} )}^{2} - {( \sqrt{5} )}^{2} } \: ( a+b )( a-b ) = {a}^{2} - {b}^{2}$

$= \frac{5 \sqrt{3} + 5 \sqrt{5} }{3 - 5}$

$= \frac{5 \sqrt{3} + 5 \sqrt{5} }{ - 2}$

$= \frac{ - (5 \sqrt{3} + 5 \sqrt{5} )}{2}$

$= \frac{ - 5 \sqrt{3} - 5 \sqrt{5} }{2}$