Rationalise the following: 16 by (√41-5)
Answers
Answered by
0
Answer:
Large 6 + 1^{2} = 6 + 1 = 7 \)
\( \Large 7 + 3^{2} = 7 + 9 = 16 \)
\( \Large 16 + 5^{2} = 16 + 25 = 41 \)
\( \Large 41 + 7^{2} = 41 + 49 = 90 \)
\( \Large 90 + 9^{2} = 90 + 81 = 171 \neq 154 \)
\( \Large 171 + 11^{2} = 171 + 121 = 292 \)
Part of solved Number series questions and answers : >> Aptitude >> Number series
Similar questions