Question

Rationalise the following denominator 1/3+ root 2

Answer 1

Answer

$\frac{1}{3 + \sqrt{2} } \\ \\ = \frac{1}{3 + \sqrt{2} } \times \frac{3 - \sqrt{2} }{3 - \sqrt{2} } \\ \\ = \frac{3 - \sqrt{2} }{ {(3})^{2} - ( { \sqrt{2} }^{2} )} \\ \\ = \frac{3 - \sqrt{2} }{9 - 2} \\ \\ = \frac{3 - \sqrt{2} }{7}$

Answer 2

Refer the attachment.

Answer :

$\tt{\frac{3 - \sqrt{2} }{7}}$