Question

Rationalise the following denominator
(i). 7. (ii). 1
√12-√5. 8+3√5​

Answer 1

Answer:

1. RATIONALISE
2. √12-√5

• 144-25

119

..

$12 - \sqrt{5} x = 1 { | \frac{12 {.. {?}^{2} }^{?} }{?} | }^{2}$

1. now 2.
2. 8+3-√5
3. 11-25
4. -14

Answer 2

$\huge\color{cyan}\boxed{\colorbox{black}{ANSWER ❤}}$

(i)

$\frac{7}{ \sqrt{12} - \sqrt{5} }$

$\frac{7( \sqrt{12} + \sqrt{5} )}{( \sqrt{12} - \sqrt{5} )( \sqrt{12} + \sqrt{5} )}$

$\frac{7 \sqrt{12} + 7 \sqrt{5} }{12 - 5}$

$\frac{7 \sqrt{12} + 7 \sqrt{5} }{7}$

$\frac{7 \sqrt{12} }{7} + \frac{7 \sqrt{5} }{7}$

$\sqrt{12} + \sqrt{5}$

(ii)

$\frac{1}{8 + 3 \sqrt{5} }$

$\frac{1(8 - 3 \sqrt{5} )}{(8 + 3 \sqrt{5})(8 - 3 \sqrt{5} ) }$

$\frac{8 - 3 \sqrt{5} }{64 - 45}$

$\frac{8 - 3 \sqrt{5} }{19}$